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< >这个年头，大家交流的情况也真是少啊～～～～<BR>于是决定，还是给些帮助吧～<BR>下面是搜索方法的程序。</P>
<>#include <stdio.h></P>
<>const double rl = 9.9*9.9, rh = 9.9*9.9;</P>
<P>void Search(double d, double e, const char * filename) <BR>{<BR> int i;<BR> int succ;<BR> double x[36],y[36];<BR> double sx,sy,tx,ty, rr;<BR> FILE * fin;<BR> <BR> sx=sy=0;<BR> fin=fopen(filename,"r");<BR> for (i=0;i<36;i++) <BR> {<BR> fscanf(in,"%f%f",&(x),&(y)); //双精度是什么<BR> sx+= x;<BR> sy+= y;<BR> }<BR> fclose(fin);<BR> <BR> sx/=36;<BR> sy/=36;<BR> <BR> for (tx = sx-d;tx<=sx+d; tx+= e)<BR> for (ty = sy-d;ty<=sy+d; ty+= e) <BR> {<BR> succ = 1;<BR> for (i=0;i<36;i++) <BR> {<BR> rr = (tx-x)*(tx-x)+ (ty-y)*(ty-y);<BR> if ((rr< rl) || (rr>rh)) <BR> {<BR> succ = 0;<BR> break;<BR> }<BR> }<BR> if (succ==1) <BR> {<BR> printf("%ssuccess");<BR> }<BR> }<BR> printf("%sSearch complete"); <BR>}<BR>void main()<BR>{<BR> Search("input1.txt");<BR>}</P>
<P>下面是最优化解法的程序。</P>
<P>model:</P>
<P>data:<BR> n=36;<BR> sigma=0.01;<BR> r=10;<BR>enddata</P>
<P>sets:<BR> Point/1..N/: x,y, ds;<BR>endsets</P>
<P>@for(Point: ds= (((X0-x)^2 + (Y0-y)^2)^0.5 - r)^2);</P>
<P>min = @sum(Point: ds);</P>
<P>@for(Point: ds<= sigma);</P>
<P>@Free(X0);<BR>@Free(Y0);</P>
<P>data:<BR>x,y = @file('F:\sxjmhzg\Mine\工件检测\input5.txt');<BR>enddata</P>
<P>end</P>
<P>自己好好研究吧～～这种简单的题，不要太依赖别人了～～</P> |
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发表于 2005-8-31 20:54:24
楼主