程序1 求初解
& l4 k* w' V/ f+ _" jclc,clear
% }2 x" h4 g3 X XA1=eye(6,6);, \& q+ e! M4 g1 F. x
A2=eye(4,4);( U9 R9 ^' s; V: ^
B1=A1(1:5, ;% ~3 G- ]# q8 g0 B! D
B2=A2(1, ;
d6 l K8 o. `, q- l. c4 nX1=[A1;A1;A1;A1;B1];7 {- ^+ I9 ~ J% {! Q( a# [( J
X4=[A2;A2;A2;A2;A2;A2;A2;B2];; k! `& B) ^) `. r7 E
%以下程序用于求解X2,X3中1-9个决策变量: C) D( `# I2 K
P1=X1;t=0;* a4 E, \& E% h5 p& v4 f; m& A* ~
While (t<2)9 `" i P& }2 g3 F+ b" E) C- A$ `
X=zeros(29,6);8 y4 [: t/ y) S
c11=zeros(1,6);; {4 j5 S9 S+ C2 t; l* Y! ^6 S
c1=zeros(1,6);; ^4 Y7 n9 B+ b
count=0;
& S' B: C, b: \. D6 L, H2 w) {for m=1:91 K9 X* F! D# U! V5 G+ h
tag11=0;
8 G- k5 D V# mfor n=1:6& O8 B$ S4 r0 N1 C) [6 h% M9 e
if P1(m,n)==09 B) L0 [2 g# o* b% _+ @1 o$ `
if c11(n)<2&tag11==0&count<3
0 S: y: q6 u. T; e; Z( wX(m,n)=1;. {2 l, u! S% |* K2 g, E
tag11=1;
, v% J: ~3 }0 ]( g8 n0 m8 zc11(n)=c11(n)+1;6 I. b( K" G( L) u7 R9 F
c1(n)=c1(n)+1;
( t* Y+ Y: D* Q! I5 Y8 Eif c11(n)==2
7 T, J) s" r' r/ K3 H4 o- |7 V4 l3 Fcount=count+1;
1 U" r: y. d! _, Q5 ^* aend
" _! X3 {# s; I5 ^elseif c11(n)<1&tag11==0
1 ?1 I/ m9 ]/ F( q! S; v& ?, v! iX(m,n)=1;5 s" s6 e4 a9 x
tag11=1;
* J1 F7 {1 _5 c) A oc11(n)=c11(n)+1;
/ j# \3 v. _- l* c3 l$ L. L7 v8 Bc1(n)=c1(n)+1;$ H8 `) r3 ~3 x) m: M2 Y
end
3 [% K! C4 [1 j8 Vend m% S0 @& C i* ]. I4 t
end
) y/ C# j/ X; E6 e$ I. o4 X6 v! mend8 s6 C7 D* D# Z* a& v& t
%以下程序用于调整X3中前9行中不满足条件的决策变量# ]) Z+ u+ E; g4 o$ Y
If t==1
( I- W1 N+ Q, N/ t- T7 J7 ~a=sum(X(1:9, ′);' }: K: V+ v6 s- [8 }; o
for m=1:9
8 W! I% ]3 m& v9 k) [6 l1 [if a(m)==0/ Z/ q3 o- O4 p1 y0 t
b=m;
+ Q* Y! y: F# Dbreak;1 P4 R/ L3 J6 W2 T/ N1 c
end
5 Y" z/ b* M3 v4 b5 Rend
9 j/ K2 X2 E+ M" L# R$ lY=X(1:9,:);; U9 K( ~. ?+ ^! y5 K0 s, U& M
for m=1:9
5 D$ ?2 V, J: K* {! qkk=0;
: X" ~0 ?! D2 O; ac=P1(b,:)+Y(m,:);: M( i# t# S4 p3 b
for n=1:6
! p6 N0 M ^& e: J' @if c(n)==2
7 |- ~& |$ p+ j" d0 r, Pkk=1;
- {( Q; H0 y2 zbreak0 q. u: m1 U' C5 p h* n8 D( ]
end
9 P8 ` }& y. {) N" |5 Nend. C, l2 K* s( C. A. c
if kk==0
$ S% l# t( H9 B" m4 iX(b,:)=Y(m,:);
! B' W6 L7 m/ jX(m,:)=Y(b,:);+ C0 \+ w0 W+ m9 s% ^2 a, [
for n=1:6, R5 z+ t8 T5 m. x$ {! b" c
if P1(m,n)==0& ~% ?4 t1 R, G/ G
X(m,n)=1;
4 ?: G) m2 C8 x& P) wbreak
& D6 s( L2 w0 J$ L1 g7 Wend
6 ?" {$ v& y( I2 @4 p, w* a% eend
- X. ]" K* |5 J# X3 f; tbreak
$ U5 s W( w; F& y0 Tend
" j7 E( p' Q5 {8 J- f: g8 u4 Q! f- send
4 q7 {: ]) ~$ B4 Q& M4 L7 Aend& V: L% O; y2 G) |' E- y( g
) ~1 b; x' X& f% `+ S4 c%以下程序用于求解X2,X3中20-29个决策变量
8 R: |6 |! G3 F4 lFor m=10:291 l7 u6 g, V m( r5 o2 |! }
tag12=0;' \* L& U% p7 v. `7 s: ], \/ f
for n=1:69 v& x' F5 f2 j( E4 d
if P1(m,n)==0& [2 ~$ M. J- J" Y9 _
if c1(n)<5&tag12==0
. }$ R# U) F Q5 Y- x; CX(m,n)=1;! [! ?3 O. H1 A" p# E+ y
tag12=1;
, Q) u, i( B' L& g% f' w8 Ec1(n)=c1(n)+1;
* Q1 i- J3 k+ N1 f0 Aelse" @1 F- z! a- Z; |
X(m,n)=0;
7 n0 S8 a [+ e" z7 b, X1 \- U3 zend
) j- i9 F- a5 T- g9 jelse! f6 p0 H% \$ j* j8 z
X(m,n)=0;2 E4 ~& m o: E3 I3 _
end# k; J: S4 @8 H& b; L
end+ L: L) \( \. s4 u$ y
end
: T1 q' v: b8 u9 k# @+ r+ f; Z%以下程序用于调整X3中20-29个不满足条件的决策变量% Z3 N+ C# }" A8 m$ {7 T
if t==17 G7 [3 b& f- E
Y=X+ Z) Y! G0 @! y% Q+ o
For m=10:292 G2 n N o0 \
if P1(m,6)==0# M% h5 M. V" F; W0 u; m0 t
X(m,:)=Y(29,:);/ b9 Z' y' T/ ~6 r. E6 _
X(29,:)=Y(m,:);
$ _! j8 ~; f% l4 Y$ p% T# eX(m,6)=1;: b: m: d& L- a/ I7 {
break/ D9 S) v9 X# {( u" q
end
5 P* k2 A2 S5 f1 r3 o- V' iend
; i b2 g9 o4 K: T8 h4 c6 Rend
# `6 f' g( U7 ^6 `
" g$ h2 ?. ^& ?# ~& }) D# V/ E+ U6 nif t==0& a% e9 u3 b. V7 c- W! |$ ~) p& o
X2=X;( e( ?" d, x6 \5 v5 ]
else, q/ h3 F( n, d' @$ E4 w$ ~
X3=X;
% p3 {% S& v# H0 L5 e$ _end, ?0 m0 a: i; M6 H) C
P1=P1+X;
9 u7 ^4 Z1 G( x9 L1 Dt=t+1;
9 C% ?+ n- f" z0 R' I( w/ |* |: bend& t; Q: M* b# ?
%以下程序用以求得满足约束条件的X5,X6,X7; I( y& \1 j- E/ g" D3 U7 p: n& |
t=0;
4 u- B. e( N4 ~while (t<3)
& u; v3 C5 I! u4 w& x9 Z0 M/ @C2=randperm1(A2);
# h/ G+ b1 Z4 V* h: A. LB2= C2(1,:);
( N) e# L" Q; Y: }Y=[randperm1(A2); randperm1(A2); randperm1(A2); randperm1(A2);
! P) P' Z+ j$ a! ~% y3 y$ @( O) Irandperm1(A2); randperm1(A2); randperm1(A2);B2];0 G$ F/ ^ Y: l+ c
if t==0
- L: R" ]; ^* m! P6 \: ~6 U! T7 GX5=Y;4 s& T- A3 H0 e9 ~; o3 K/ V6 d% o1 G
elseif t==1
% ~* N2 L' [1 ]8 R" _& H+ j3 m% g+ sX6=Y;
! K$ |/ u0 g! n+ }/ e* uelse1 N. M* x9 \) k% R) v- N& X& `1 H
X7=Y;( p# i1 {6 I' Y# J# A4 p
end+ b3 j2 x8 w$ Y! z# S7 q
t=t+1;. `9 E( e* O6 G, I; T+ e
end
' n# {8 g( B3 R2 l/ u% }%将初解保存在文本文件shuju中
. P& z$ c/ f) o4 f% [Save shuju X1 X2 X3 X4 X5 X6 X7. M4 a% @; v8 h
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